Your Answers 
(12/08) Patrick Sabaruddin : 2
Shika : Wrong.

(11/08) Brad Mayne : i dont think there will be any left over cause as it says every one will have the chance to fight
Shika : I don't see how your reasoning leads to your conclusion. Any way its wrong.

(10/08) Patrick Sabaruddin : the answer is 2 If Iruka sensei discoverd that in the second round that by relabelling the ninjas he could make it exactly as the first round this means that the ninjas fight the same number of people as in the first round. Meaning that the number of ninjas are even, because if there were odd numbers Iruka sensei couldn't relabel the ninja's because he'd have some left over (as odd multiples are not divisible by even numbers). Hence the remainding ninja's are either nothing or 2.
hope my logic makes sense... i can't really express myself too well ^^
Shika : There is a lapse in your reasoning.

(09/08) NiteNemises : Not enough information or. . . .
1
2
3
4
......................
2
3
4
1
......................
3
4
1
2
........................
4
1
2
3
........................
12 is my off the wall answer.
Shika : Well I don't know what to say. Maybe you can explain it abit more? And rest assured that enough info is provided

(06/08) Bob Kunz : The answer to your riddle: (assuming 4 students are playing the 2 rounds together)
There are 6 possible combinations:
12,13,14
23,24
34
So in order for the two tables to be equal, we need to have 3 matches per round. No combination will left out so I'm assuming the number of
students "leftover" will be 0.
In Round A:
1 fights 3 and 4
2 fights 3
In Round B, Students are renumbered by adding 1 to their current number (modulo 4) So for instance:
1 becomes 2
2 becomes 3
3 becomes 4
4 becomes 1 (4+1) mod 4
In this case, the fight table for Round B looks like so:
1 fights 3 and 4 (would be 4 fights 2 and 3 without reordering)
2 fights 3 (would be 1 fights 2 without reordering)
Round A == Round B
Therefore, all six combinations are covered.
Shika : Wrong, plus you're making too many assumptions :P

(06/08) May Miyaoka : This is my idea, If the students are divided into squads of 4, and there are students left over, there would be either 1, 2 or 3 students left. It is not possible to have 4 or more left over because you could make more squads of 4 and if there was more, there would still be 1, 2 or 3 left anyways.
Shika : If yours is the correct answer, then I wouldn't need to tell you that long story, would I ?

